This is how I was taught this many years ago.
Signals actually travel through microscopic air pockets in the dielectric material "bouncing" between the center conductor and shield.
Since the wavelength of a signal shortens as frequency increases, the higher frequencies have to actually travel farther than the lower frequencies to reach the termination point.
That is why the loss of signal is greater as frequency increases.
Remember "air dielectric" and "disc" cable.
Re: COAX Diagram
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